A projectile is fired at 60 m/s at a 30-degree angle. Using g = 9.81 m/s^2, its horizontal range is approximately how many meters?

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Multiple Choice

A projectile is fired at 60 m/s at a 30-degree angle. Using g = 9.81 m/s^2, its horizontal range is approximately how many meters?

Explanation:
For a projectile launched and landing at the same height, the horizontal range is R = v^2 sin(2θ) / g. Here v = 60 m/s and θ = 30°, so 2θ = 60° and sin 60° ≈ 0.866. Plugging in: R = (60^2 × 0.866) / 9.81 = (3600 × 0.866) / 9.81 ≈ 3117.6 / 9.81 ≈ 318 meters. So the approximate range is about 318 meters.

For a projectile launched and landing at the same height, the horizontal range is R = v^2 sin(2θ) / g. Here v = 60 m/s and θ = 30°, so 2θ = 60° and sin 60° ≈ 0.866. Plugging in: R = (60^2 × 0.866) / 9.81 = (3600 × 0.866) / 9.81 ≈ 3117.6 / 9.81 ≈ 318 meters. So the approximate range is about 318 meters.

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