A rectangle with perimeter 40 units has length 11; what is width?

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Multiple Choice

A rectangle with perimeter 40 units has length 11; what is width?

Explanation:
Use the rectangle perimeter idea: P = 2(L + W). With P = 40 and L = 11, 40 = 2(11 + W). Divide by 2 to get 20 = 11 + W, so W = 9. This width makes L + W = 20, giving P = 2(20) = 40, which matches. The other values would make the sum L + W larger (for example, 11 would make it 22, giving P = 44; 20 would give P = 62; 15 would give P = 52), which doesn’t fit the given perimeter. Width is 9 units.

Use the rectangle perimeter idea: P = 2(L + W). With P = 40 and L = 11, 40 = 2(11 + W). Divide by 2 to get 20 = 11 + W, so W = 9. This width makes L + W = 20, giving P = 2(20) = 40, which matches. The other values would make the sum L + W larger (for example, 11 would make it 22, giving P = 44; 20 would give P = 62; 15 would give P = 52), which doesn’t fit the given perimeter. Width is 9 units.

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