If a battery loses 2% per hour, how many hours to reach 50% capacity assuming linear decay?

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Multiple Choice

If a battery loses 2% per hour, how many hours to reach 50% capacity assuming linear decay?

Explanation:
With linear decay, you lose a constant amount of capacity each hour. Here that rate is 2 percentage points per hour, so the remaining capacity after t hours is 100% − 2t%. To reach 50% remaining, set 100 − 2t = 50. Subtract 100 from both sides and divide by 2: 2t = 50 → t = 25 hours. Check the other options quickly: after 20 hours you’d be at 60%, after 30 hours you’d be at 40%, and after 40 hours you’d be at 20%. Only 25 hours drops you to 50%.

With linear decay, you lose a constant amount of capacity each hour. Here that rate is 2 percentage points per hour, so the remaining capacity after t hours is 100% − 2t%.

To reach 50% remaining, set 100 − 2t = 50. Subtract 100 from both sides and divide by 2: 2t = 50 → t = 25 hours.

Check the other options quickly: after 20 hours you’d be at 60%, after 30 hours you’d be at 40%, and after 40 hours you’d be at 20%. Only 25 hours drops you to 50%.

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